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प्रश्न
Expand the following:
`(2x - 1/3 y)^2`
योग
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उत्तर
Given: `(2x - 1/3 y)^2`
Step-wise calculation using the identity (a – b)2 = a2 – 2ab + b2:
1. `a = 2x` and `b = 1/3 y`
2. Square of first term:
(2x)2 = 4x2
3. Twice the product of the two terms:
`2 xx 2x xx 1/3 y = 4/3 xy`
4. Square of the second term:
`(1/3 y)^2 = 1/9 y^2`
5. Combine with subtraction because of the minus sign:
`(2x - 1/3 y)^2 = 4x^2 - 4/3 xy + 1/9 y^2`
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अध्याय 3: Expansions - Exercise 3A [पृष्ठ ६४]
