Advertisements
Advertisements
प्रश्न
Expand the following:
`(2"a" + 1/(2"a"))^2`
Advertisements
उत्तर
`(2"a" + 1/(2"a"))^2`
= `(2"a")^2 + 2(2"a") (1/(2"a")) + 2"a"^2`
= `4"a"^2 + 2 + (1)/(4"a"^2)`.
APPEARS IN
संबंधित प्रश्न
Use suitable identity to find the following product:
(3 – 2x) (3 + 2x)
Write the following cube in expanded form:
`[3/2x+1]^3`
Write the following cube in expanded form:
`[x-2/3y]^3`
If 3x - 7y = 10 and xy = -1, find the value of `9x^2 + 49y^2`
If a + b = 10 and ab = 21, find the value of a3 + b3
If x = −2 and y = 1, by using an identity find the value of the following
\[\frac{( a^2 - b^2 )^3 + ( b^2 - c^2 )^3 + ( c^2 - a^2 )^3}{(a - b )^3 + (b - c )^3 + (c - a )^3} =\]
Use the direct method to evaluate :
(3x2+5y2) (3x2−5y2)
Simplify by using formula :
(2x + 3y) (2x - 3y)
Simplify by using formula :
`("a" + 2/"a" - 1) ("a" - 2/"a" - 1)`
