Question

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`(2p - 1/(2p))^3`

Answer 1

`(2p - 1/(2p))^3`

`(a - b)^3 = a^3 - 3a^2b + 3ab^2 - b^3`

= `(2p)^3 - 3 xx (2p)^2 xx 1/(2p) + 3 xx 2p xx (1/(2p))^2 - (1/(2p))^3`

= `8p^3 - 3 xx 4p^2 xx 1/(2p) + 3 xx 2p xx 1/ (4p^2) - 1/(8p^3)`

= `8p^3 - 3 xx 4p xx 1/2 + 3 xx 2 xx 1/(4p) - 1/ (8p^3)`

= `8p^3 - 3 xx 2p xx 1/1 + (3 xx 1)/(2p) - 1/(8p^3)`

= `8p^3 - 6p + 3/(2p) - 1/(8p^3)`