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प्रश्न
Example of contingent annuity is ___________.
विकल्प
Installments of payment for a plot of land
An endowment fund to give scholarships to a student
Personal loan from a bank
All the above
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उत्तर
Example of contingent annuity is An endowment fund to give scholarships to a student.
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संबंधित प्रश्न
Find the amount of an ordinary annuity of ₹ 3,200 per annum for 12 years at the rate of interest of 10% per year. [(1.1)12 = 3.1384]
If the payment of ₹ 2,000 is made at the end of every quarter for 10 years at the rate of 8% per year, then find the amount of annuity. [(1.02)40 = 2.2080]
A person deposits ₹ 2,000 at the end of every month from his salary towards his contributory pension scheme. The same amount is credited by his employer also. If 8% rate of compound interest is paid, then find the maturity amount at end of 20 years of service. [(1.0067)240 = 4.9661]
Find the present value of ₹ 2,000 per annum for 14 years at the rate of interest of 10% per annum. If the payments are made at the end of each payment period. [(1.1)–14 = 0.2632]
Find the amount at the end of 12 years of an annuity of ₹ 5,000 payable at the beginning of each year, if the money is compounded at 10% per annum. [(1.1)12 = 3.1384]
What is the present value of an annuity due of ₹ 1,500 for 16 years at 8% per annum? What is the present value of an annuity due of ₹ 1,500 for 16 years at 8% per annum? [(1.08)16 = 3.172]
The present value of the perpetual annuity of ₹ 2000 paid monthly at 10% compound interest is ___________.
Find the amount of annuity of ₹ 2000 payable at the end of each year for 4 years of money is worth 10% compounded annually. [(1.1)4 = 1.4641]
Find the amount of an ordinary annuity of ₹ 600 is made at the end of every quarter for 10 years at the rate of 4% per year compounded quarterly. [(1.01)40 = 1.4889]
Naveen deposits ₹ 250 at the end of each month in an account that pays an interest of 6% per annum compounded monthly, how many months will be required for the deposit to amount to at least ₹ 6390? [log(1.1278) = 0.0523, log(1.005) = 0.0022]
