Advertisements
Advertisements
प्रश्न
Find the present value of ₹ 2,000 per annum for 14 years at the rate of interest of 10% per annum. If the payments are made at the end of each payment period. [(1.1)–14 = 0.2632]
Advertisements
उत्तर
Here a = 2000, n = 14, and i = `10/100` = 0.1
P = `"a"/"i" [1 - 1/(1 + "i")^"n"]`
= `2000/0.1 [1 - 1/(1 + 0.1)^14]`
= `2000/0.1 [1 - (1.1)^(-14)]`
= 20000 [1 – 0.2632]
= 20000 × 0.73678
= ₹ 14,735.60
APPEARS IN
संबंधित प्रश्न
If the payment of ₹ 2,000 is made at the end of every quarter for 10 years at the rate of 8% per year, then find the amount of annuity. [(1.02)40 = 2.2080]
Find the present value of an annuity of ₹ 900 payable at the end of 6th month for 6 years. The money compounded at 8% per annum. [(1.04)–12 = 0.6252]
What is the amount of perpetual annuity of ₹ 50 at 5% compound interest per year?
₹ 5000 is paid as perpetual annuity every year and the rate of C.I. 10%. Then present value P of immediate annuity is __________.
If ‘a’ is the annual payment, ‘n’ is the number of periods and ‘i’ is compound interest for ₹ 1 then future amount of the ordinary annuity is
The present value of the perpetual annuity of ₹ 2000 paid monthly at 10% compound interest is ___________.
Calculate the amount of an ordinary annuity of ₹ 10,000 payable at the end of each half-year for 5 years at 10% per year compounded half-yearly. [(1.05)10 = 1.6289]
Find the amount of an ordinary annuity of ₹ 600 is made at the end of every quarter for 10 years at the rate of 4% per year compounded quarterly. [(1.01)40 = 1.4889]
A cash prize of ₹ 1,500 is given to the student standing first in examination of Business Mathematics by a person every year. Find out the sum that the person has to deposit to meet this expense. Rate of interest is 12% p.a.
Machine A costs ₹ 15,000 and machine B costs ₹ 20,000. The annual income from A and B are ₹ 4,000 and ₹ 7,000 respectively. Machine A has a life of 4 years and B has a life of 7 years. Find which machine may be purchased. (Assume discount rate 8% p.a) [(1.08)–4 = 0.7350, (1.08)–7 = 0.5835]
