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Evaluate the following: log_16 32 – log_9 27 - Mathematics

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प्रश्न

Evaluate the following:

log16 32 – log9 27

मूल्यांकन
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उत्तर

Given: log16 32 – log9 27

Step-wise calculation:

1. log16 32

= `(log_2 32)/(log_2 16)`

= `5/4`

Because 32 = 25 and 16 = 24.

2. log9 27 

= `(log_3 27)/(log_3 9)`

= `3/2`

Because 27 = 33 and 9 = 32.

3. Subtract:

`5/4 - 3/2`

= `5/4 - 6/4`

= `-1/4`

`log_16 32 - log_9 27 = -1/4 (-0.25)`.

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अध्याय 7: Logarithms - Exercise 7B [पृष्ठ १४६]

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नूतन Mathematics [English] Class 9 ICSE
अध्याय 7 Logarithms
Exercise 7B | Q 2. (i) | पृष्ठ १४६
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