हिंदी

Evaluate the following limits: limx→2[x2-4x+2-3x-2] - Mathematics and Statistics

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प्रश्न

Evaluate the following limits: `lim_(x -> 2)[(x^2 - 4)/(sqrt(x + 2) - sqrt(3x - 2))]`

योग
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उत्तर

`lim_(x -> 2)[(x^2 - 4)/(sqrt(x + 2) - sqrt(3x - 2))]`

= `lim_(x -> 2) [(x^2 - 4)/(sqrt(x + 2) - sqrt(3x - 2)) xx(sqrt(x + 2) + sqrt(3x - 2))/(sqrt(x + 2) + sqrt(3x - 2))]`

= `lim_(x -> 2) ((x^2 - 4)(sqrt(x + 2) + sqrt(3x - 2)))/((x + 2) - (3x - 2)`

= `lim_(x -> 2) ((x^2 - 4)(sqrt(x + 2) + sqrt(3x - 2)))/(-2x + 4)`

= `lim_(x -> 2) ((x + 2)(x - 2)(sqrt(x + 2) + sqrt(3x - 2)))/(-2(x - 2)`

= `lim_(x -> 2) ((x + 2)(sqrt(x + 2) + sqrt(3x - 2)))/(-2)   ...[("As"  x -> 2"," x ≠ 2),(therefore x - 2 ≠0)]`

= `((2 + 2)(sqrt(2 + 2) + sqrt(3(2) - 2)))/(-2)`

= `(4(2 + 2))/(-2)`

= `16/(-2)`

= – 8

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अध्याय 7: Limits - EXERCISE 7.3 [पृष्ठ १०३]

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बालभारती Mathematics and Statistics 1 (Commerce) [English] Standard 11 Maharashtra State Board
अध्याय 7 Limits
EXERCISE 7.3 | Q II. 2. | पृष्ठ १०३
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