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Evaluate the following limit : limx→2[x2+x2-4x2-3x2+4] - Mathematics and Statistics

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प्रश्न

Evaluate the following limit :

`lim_(x -> sqrt(2)) [(x^2 + xsqrt(2) - 4)/(x^2 - 3xsqrt(2) + 4)]`

योग
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उत्तर

`lim_(x -> sqrt(2)) [(x^2 + xsqrt(2) - 4)/(x^2 - 3xsqrt(2) + 4)]`

Consider, `x^2 + xsqrt(2) - 4 = x^2 + sqrt(2) x - 4`

= `x^2 + 2sqrt(2)x - sqrt(2)x - 4`

= `x(x + 2sqrt(2)) - sqrt(2)(x + 2sqrt(2))`

= `(x + 2sqrt(2)) (x - sqrt(2))`

`x^2 - 3x sqrt(2) + 4 = x^2 - 3sqrt(2)x + 4`

= `x^2 - 2sqrt(2)x - sqrt(2)x + 4`

= `x(x - 2sqrt(2)) - sqrt(2)(x - 2sqrt(2))`

= `(x - 2sqrt(2)) (x - sqrt(2))`

Now, `lim_(x -> sqrt(2)) [(x^2 + xsqrt(2) - 4)/(x^2 - 3xsqrt(2) + 4)]`

= `lim_(x -> sqrt(2)) ((x + 2sqrt(2))(x - sqrt(2)))/((x - 2sqrt(2))(x - sqrt(2))`

= `lim_(x -> sqrt(2)) (x + 2sqrt(2))/(x - 2sqrt(2))  ...[(because  x -> sqrt(2)","  therefore x ≠ sqrt(2)","),(therefore x - sqrt(2)≠ 0)]`

= `(lim_(x -> sqrt(2))(x + 2sqrt(2)))/(lim_(x -> sqrt(2))(x - 2sqrt(2))`

= `(sqrt(2) + 2sqrt(2))/(sqrt(2) - 2sqrt(2))`

= `(3sqrt(2))/(-sqrt(2))`

= – 3

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अध्याय 7: Limits - Exercise 7.2 [पृष्ठ १४१]

APPEARS IN

बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 11 Maharashtra State Board
अध्याय 7 Limits
Exercise 7.2 | Q II. (5) | पृष्ठ १४१

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