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Evaluate the following: d∫01xdx1+x2 - Mathematics

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प्रश्न

Evaluate the following:

`int_0^1 (x"d"x)/sqrt(1 + x^2)`

योग
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उत्तर

Let I = `int_0^1 (x"d"x)/sqrt(1 + x^2)`

Put 1 + x2 = t

⇒ 2x dx = dt

⇒ x dx = `"dt"/2`

Changing the limits, we have

When x = 0

∴ t = 1

When x = 1

∴ t = 2

∴ I = `1/2 int_1^2 "dt"/sqrt("t")`

= `1/2 * 2["t"^(1/2)]_1^2`

= `sqrt(2) - 1`

Hence, I =  `sqrt(2) - 1`.

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अध्याय 7: Integrals - Exercise [पृष्ठ १६५]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 12
अध्याय 7 Integrals
Exercise | Q 32 | पृष्ठ १६५

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