Evaluate the Following: ( 2 3 ) 2 - Mathematics

Evaluate the following: `(2^3)^2`

योग

`(2^3)^2`
= 2⁶
= 64

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Laws of Exponents

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अध्याय 9: Indices - Exercise 9.1

अध्याय 9 Indices
Exercise 9.1 | Q 1.03

Evaluate:

`5^(-4) xx ( 125)^(5/3) ÷ (25)^(-1/2)`

Evaluate:

`( 27/125 )^(2/3) xx ( 9/25 )^(-3/2)`

Simplify :
`( 8x^3 ÷ 125y^3 )^(2/3)`

Simplify:

`[ 5^( n + 3 ) - 6 xx 5^( n + 1 )]/[ 9 xx 5^n - 5^n xx 2^2 ]`

Simplify the following and express with positive index :
`(3^-4/2^-8)^(1/4)`

If 2160 = 2^a. 3^b. 5^c, find a, b and c. Hence calculate the value of 3^a x 2^-b x 5^-c.

Simplify:

`[ 3 xx 27^( n + 1 ) + 9 xx 3^(3n - 1 )]/[ 8 xx 3^(3n) - 5 xx 27^n ]`

Evaluate the following: `(3^2)^2`

Find the value of (2³)².

`[(3/7)^-3]^4` = ______