Evaluate the Following: ( 2 3 ) 2

Evaluate the following: `(2^3)^2`

योग

`(2^3)^2`
= 2⁶
= 64

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Laws of Exponents

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अध्याय 9: Indices - Exercise 9.1

अध्याय 9 Indices
Exercise 9.1 | Q 1.03

Evaluate :
`3^3 xx ( 243 )^(-2/3) xx 9^(-1/3)`

Evaluate:

`( 27/125 )^(2/3) xx ( 9/25 )^(-3/2)`

Evaluate:

`7^0 xx (25)^(-3/2) - 5^(-3)`

Simplify :
`( 8x^3 ÷ 125y^3 )^(2/3)`

Simplify the following and express with positive index:

`[ 1 - { 1 - ( 1 - n )^-1}^-1]^-1`

If 2160 = 2^a. 3^b. 5^c, find a, b and c. Hence calculate the value of 3^a x 2^-b x 5^-c.

Simplify:

`[ 3 xx 27^( n + 1 ) + 9 xx 3^(3n - 1 )]/[ 8 xx 3^(3n) - 5 xx 27^n ]`

Show that :
`( a^m/a^-n)^( m - n ) xx (a^n/a^-l)^( n - l) xx (a^l/a^-m)^( l - m ) = 1`

Simplify:

`( x^a/x^-b )^( a^2 - ab + b^2 ) xx ( x^b/x^-c )^( b^2 - bc + c^2 ) xx ( x^c/x^-a )^( c^2 - ca + a^2 )`

Find the value of 4⁶ × 4⁻⁴.