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Evaluate the following : ∫0π4tan3x1+cos2x⋅dx - Mathematics and Statistics

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प्रश्न

Evaluate the following : `int_0^(pi/4) (tan^3x)/(1 +cos2x)*dx`

योग
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उत्तर

Let I = `int_0^(pi/4) (tan^3x)/(1 +cos2x)*dx`

= `int_0^(pi/4) (tan^3x)/(2cos^2x)*dx`

= `(1)/(2) int_0^(pi/4) tan^3x*sec^2x*dx`

Put tan x = t
∴ sec2x·dx = dt
When x = 0, t = tan 0 = 0

When x = `pi/(4), t = tan  pi/(4)` = 1

∴ I = `(1)/(2) int_0^1 t^3*dt`

= `(1)/(2)*[(t^4)/4]_0^1`

= `(1)/(8)[t^4]_0^1`

= `(1)/(8)[1 - 0]`

= `(1)/(8)`.

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 4: Definite Integration - Miscellaneous Exercise 4 [पृष्ठ १७६]

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बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
अध्याय 4 Definite Integration
Miscellaneous Exercise 4 | Q 2.04 | पृष्ठ १७६
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