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प्रश्न
Evaluate: `int_(pi/12)^((5pi)/12)dx/(1+sqrtcotx)`
मूल्यांकन
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उत्तर
Let I = `int_(pi/12)^((5pi)/12)dx/(1+sqrtcotx)`
I = `int_(pi/12)^((5pi)/12)dx/(1+sqrt(cosx)/sqrtsinx)`
= `int_(pi/12)^((5pi)/12)sqrtsinx/(sqrtsinx+sqrtcosx)dx` ...(I)
Put: `int_a^bf(x)dx=int_a^b(a+b-x)dx`
I = `int_(pi/12)^((5pi)/12)(sqrtsin(pi/2-x))/(sqrtsin(pi/2-x)+sqrt(cos(pi/2-x)))dx`
= `int_(pi/12)^((5pi)/12)sqrtcosx/(sqrtcosx+sqrtsinx)dx` ...(II)
Adding (I) and (II)
2I = `int_(pi/12)^((5pi)/12)(sqrtsinx/(sqrtsinx+sqrtcosx)+sqrtcosx/(sqrtcosx+sqrtsinx))dx`
2I = `int_(pi/12)^((5pi)/12)dx`
2I = `[x]_(pi/12)^((5pi)/12)`
2I = `(5pi)/12-pi/12`
2I = `(4pi)/12`
2I = `pi/3`
I = `pi/6`
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