हिंदी

Evaluate: 1integral4 {|X -1|+|X - 2|+|X - 4|}Dx` - Mathematics

Advertisements
Advertisements

प्रश्न

Evaluate: `int_1^4 {|x -1|+|x - 2|+|x - 4|}dx`

Advertisements

उत्तर १

I = `int_1^4 (|x -1|+|x - 2|+|x - 4|)dx`

Let f (x) = |x - 1| + |x - 2| + |x - 4|

We have three critical points x = 1, 2, 4

(i) when x <1

(ii) when 1≤ x < 2

(iii) when 2 ≤ x < 4

(iv) when x ≥ 4

shaalaa.com

उत्तर २

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
2016-2017 (March) All India Set 1

संबंधित प्रश्न

Prove that: `int_0^(2a)f(x)dx=int_0^af(x)dx+int_0^af(2a-x)dx`


Evaluate : `intsec^nxtanxdx`


By using the properties of the definite integral, evaluate the integral:

`int_0^(pi/2)  (cos^5  xdx)/(sin^5 x + cos^5 x)`


By using the properties of the definite integral, evaluate the integral:

`int_2^8 |x - 5| dx`


By using the properties of the definite integral, evaluate the integral:

`int_0^1 x(1-x)^n dx`


By using the properties of the definite integral, evaluate the integral:

`int_0^pi log(1+ cos x) dx`


Show that `int_0^a f(x)g (x)dx = 2 int_0^a f(x) dx`  if f and g are defined as f(x) = f(a-x) and g(x) + g(a-x) = 4.


Evaluate the definite integrals `int_0^pi (x tan x)/(sec x + tan x)dx`


Evaluate`int (1)/(x(3+log x))dx` 


Evaluate : `int _0^(pi/2) "sin"^ 2  "x"  "dx"`


Evaluate = `int (tan x)/(sec x + tan x)` . dx


Find : `int_  (2"x"+1)/(("x"^2+1)("x"^2+4))d"x"`.


`int_0^(pi/4) (sec^2 x)/((1 + tan x)(2 + tan x))`dx = ?


If `int_0^"a" sqrt("a - x"/x) "dx" = "K"/2`, then K = ______.


`int_0^1 x tan^-1x  dx` = ______ 


If f(x) = |x - 2|, then `int_-2^3 f(x) dx` is ______


`int_0^{1/sqrt2} (sin^-1x)/(1 - x^2)^{3/2} dx` = ______ 


`int_0^{pi/2} (cos2x)/(cosx + sinx)dx` = ______


Find `int_2^8 sqrt(10 - x)/(sqrt(x) + sqrt(10 - x)) "d"x`


Find `int_0^(pi/4) sqrt(1 + sin 2x) "d"x`


`int_(-2)^2 |x cos pix| "d"x` is equal to ______.


Evaluate the following:

`int_(-pi/4)^(pi/4) log|sinx + cosx|"d"x`


`int (dx)/(e^x + e^(-x))` is equal to ______.


The value of `int_((-1)/sqrt(2))^(1/sqrt(2)) (((x + 1)/(x - 1))^2 + ((x - 1)/(x + 1))^2 - 2)^(1/2)`dx is ______.


If f(x) = `(2 - xcosx)/(2 + xcosx)` and g(x) = logex, (x > 0) then the value of the integral `int_((-π)/4)^(π/4) "g"("f"(x))"d"x` is ______.


If `int_0^K dx/(2 + 18x^2) = π/24`, then the value of K is ______.


Evaluate: `int_-1^1 x^17.cos^4x  dx`


Evaluate the following integral:

`int_-9^9 x^3 / (4 - x^2) dx`


The value of \[\int_{-1}^{1}\left(\sqrt{1+x+x^{2}}-\sqrt{1-x+x^{2}}\right)\mathrm{d}x\] is


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×