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प्रश्न
Estimate the median, the lower quartile and the upper quartile of the following frequency distribution by drawing an ogive:
| Marks (less than) | 10 | 20 | 30 | 40 | 50 | 60 | 70 | 80 |
| No. of students | 5 | 15 | 30 | 54 | 72 | 86 | 94 | 100 |
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उत्तर
Given data is a less than cumulative data , so draw the ogive as it is .
| Marks (less than) | No. of students (f) |
| 10 | 5 |
| 20 | 15 |
| 30 | 30 |
| 40 | 54 |
| 50 | 72 |
| 60 | 86 |
| 70 | 94 |
| 80 | 100 |
Take a graph paper and draw both the axes.
On the x-axis , take a scale of 1 cm = 10 to represent marks less than.
On the y-axis , take a scale of 1 cm = 20 to represents the number of students.
Now , plot the points (10,5), (20,15),(30,30),(40,54),(50,72),(60,86),(70,94),(80,100).
join them by a smooth curve to get the ogive.

No. of terms = 100
`therefore` Median = `(50 + 51)/2` = 50.5thterm
Through mark of 50.5 on y-axis draw a line parallel to x-axis which meets the curve at A. From A, draw a perpendicular to x-axis which meets is at B.
The value of B is the median which is 38.
Lower Quartile (Q1) = `n/4 = 100/4` = 25th term
Through mark of 25 on y-axis draw a line parallel to x-axis which meets the curve at P .From P , draw a perpendicular to x-axis which meets it at Q.
The value of Q is the lower Quartile which is 28.
Upper Quartile (Q3) = `(n xx 3)/4 = (100 xx 3)/4` = 75th term
Through mark of 75 on y-axis draw a line parallel to x-axis which meets the curve at R. From R, draw a perpendicular to x-axis which meets it at S.
The value of S is the upper quartile which is 51.
