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प्रश्न
Estimate the median, the lower quartile and the upper quartile of the following frequency distribution by drawing an ogive:
| Marks | 30-40 | 40-50 | 50-60 | 60-70 | 70-80 | 80-90 | 90-100 |
| No. of boys | 10 | 12 | 14 | 12 | 9 | 7 | 6 |
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उत्तर
| Marks | No. of boys (f) | Cumulative Frequency |
| 30-40 | 10 | 10 |
| 40-50 | 12 | 22 |
| 50-60 | 14 | 36 |
| 60-70 | 12 | 48 |
| 70-80 | 9 | 57 |
| 80-90 | 7 | 64 |
| 90-100 | 6 | 70 |
Take a graph paper and draw both the axes.
On the x-axis, take a scale of 1cm = 20 to represent the marks.
On the y-axis , take a scale of 1 cm = 10 to represent the number of boys.
Now , plot the points (40,10),(50,22),(60,36),(70,48),(80,57),(90,64),(100,70)
Join them by a smooth curve to get the ogive.

No. of terms = 70
∴ Median = `(35+36)/2` = 35.5th term
Through mark of 35.5 on y-axis draw a line parallel to x-axis which meets the curve at A. From A, draw a perpendicular to x-axis which meets is at B.
The value of B is the median which is 60.
Lower Quartile (Q1) = `n/4 = 70/4` = 17.5th term
Through mark of 17.5 on y-axis draw a line parallel to x-axis which meets the curve at P. From P, draw a perpendicular to x-axis which meets it at Q.
The value of Q is the lower quartile which is 47.5.
Upper Quartile (Q3) = `(n xx 3)/4 = (70 xx 3)/4` = 52.5th term
Through mark of 52.5 on y-axis draw a line parallel to x-axis which meets the curve at R, draw a perpendicular to x-axis which meets it at S.
The value of S is the upper quartile which is 74.5.
