हिंदी

Each of the equal sides of an isosceles triangle is 2 cm more than its height. If the base of triangle is 12 cm, then the area of triangle is ______. - Mathematics

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प्रश्न

Each of the equal sides of an isosceles triangle is 2 cm more than its height. If the base of triangle is 12 cm, then the area of triangle is ______.

विकल्प

  • 24 cm2

  • 36 cm2

  • 48 cm2

  • 72 cm2

MCQ
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उत्तर

Each of the equal sides of an isosceles triangle is 2 cm more than its height. If the base of triangle is 12 cm, then the area of triangle is 48 cm2.

Explanation:

Let the height = h and each equal side = h + 2.

The height and half the base `12/2 = 6` form a right triangle with the equal side as hypotenuse: 

(h + 2)2 = h2 + 62

⇒ h2 + 4h + 4 = h2 + 36

⇒ 4h = 32

⇒ h = 8 cm 

Area = `1/2` × base × height 

= `1/2 xx 12 xx 8`

= 48 cm2

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अध्याय 16: Mensuration - Exercise 16E [पृष्ठ ३४६]

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नूतन Mathematics [English] Class 9 ICSE
अध्याय 16 Mensuration
Exercise 16E | Q 3. | पृष्ठ ३४६
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