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प्रश्न
E is a point on side BC of the square ABCD, ∠AEB = 55°. find ∠EAC.

विकल्प
35°
25°
10°
15°
MCQ
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उत्तर
10°
Explanation:
Step 1: Use the properties of a square
In a square ABCD, all interior angles are 90°.
The diagonal AC bisects the angle at the vertex A,
So `∠BAC = 1/2 ∠DAB`
= `1/2 (90^circ)`
= 45°
Step 2: Find angle BAE
Consider the right-angled triangle ΔABE.
Since E is on side BC, ∠ABE = ∠ABC = 90°.
The sum of angles in a triangle is 180°.
We are given ∠AEB = 55°.
We can find ∠BAE using this information.
∠BAE + ∠ABE + ∠AEB = 180°
∠BAE + 90° + 55° = 180°
∠BAE + 145° = 180°
∠BAE = 180° – 145°
∠BAE = 35°
Step 3: Solve for angle EAC
The angle ∠EAC can be found by subtracting ∠BAE from the total angle ∠BAC.
∠EAC = ∠BAC – ∠BAE
∠EAC = 45° – 35°
∠EAC = 10°
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