Advertisements
Advertisements
प्रश्न
Draw the graph for the linear equation given below:
y = 2x + 3
Advertisements
उत्तर
First, prepare a table as follows:
| x | -1 | 0 | 1 |
| y | 1 | 3 | 5 |
Thus, the graph can be drawn as follows:
APPEARS IN
संबंधित प्रश्न
Draw the graph for the each linear equation given below:
y = `(3x)/(2) + (2)/(3)`
Draw the graph for the linear equation given below:
x - 3 = `(2)/(5)(y + 1)`
Draw the graph for the linear equation given below:
x + 5y + 2 = 0
Draw the graph for the equation given below:
2x - 5y = 10
The graph of 3x + 2y = 6 meets the x=axis at point P and the y-axis at point Q. Use the graphical method to find the co-ordinates of points P and Q.
Draw the graph of equation x + 2y - 3 = 0. From the graph, find:
(i) x1, the value of x, when y = 3
(ii) x2, the value of x, when y = - 2.
Use the graphical method to show that the straight lines given by the equations x + y = 2, x - 2y = 5 and `x/(3) + y = 0` pass through the same point.
Draw a graph of the equation 2x + 3y + 5 = 0, from the graph find the value of:
(i) x, when y = -3
(ii) y, when x = 8
Draw the graph of the lines represented by the equations x + y = 4 and 2x - y = 2 on the same graph. Find the coordinates of the point where they intersect
Draw the graph of the lines represented by the equations 3x - 2y = 4 and x + y = 3 on the same graph. Find the coordinates of the point where they intersect. State, whether the lines are perpendicular to each other.
