Question

Draw a ΔABC, right-angled at B such that AB = 3 cm and BC = 4 cm. Now, construct a triangle similar to ΔABC, each of whose sides is `7/5` times the corresponding side of ΔАВС.

Answer 1

Steps of Construction: 

Step 1: Draw a line segment BC = 4 cm.

Step 2: With B as centre, draw an angle of 90°.

Step 3: With B as centre and radius equal to 3 cm an arc at the right angle and name it A.

Step 4: Join AB and AC. Thus, ΔABC is obtained.

Step 5: Extend BC to D, such that BD = `7/5` BC = `7/5 (4)` cm = 5.6 cm.

Step 6: Draw DE || CA, cutting AB produced to E.

Thus, ΔEBD is the required triangle, each of whose sides is `7/5` the corresponding sides of ΔABC.