Question

Do the given problems by repeated subtraction method and verify the result

320, 120 and 95

Answer 1

Let us take 320 and 120 first m = 320, n = 120

m – n = 320 – 120 = 200

m = 200, n = 120

∴ m – n = 200 – 120 = 80

120 – 80 = 40

80 – 40 = 40

∴ m = n = 40 → HCF of 320, 120

Now let us find HCF of 40 and 95

m = 95, n = 40

∴ m – n = 95 – 40 = 55

55 – 40 = 15

40 – 15 = 25

25 – 15 = 10

15 – 10 = 5

HCF of 40 and 95 is 5

10 – 5 = 5

∴ HCF of 320, 120 and 95 is 5