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सी.आई.एस.सी.ई.आईसीएसई ICSE Class 6

Divide: (2"A"^2)/(9"B"^2) by (3"B")/(2"A")

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प्रश्न

Divide:

`(2"a"^2)/(9"b"^2)` by `(3"b")/(2"a")`

योग
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उत्तर

`(2"a"^2)/(9"b"^2)÷(3"b")/(2"a")`

= `(2"a"^2)/(9"b"^2)xx(2"a")/(3"b")`

= `(2xx2xx"a"^(2+1))/(9xx3"b"^(2+1))`

= `(4"a"^3)/(27"b"^3)`

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अध्याय 14: Fundamental Concepts (Including Angles and their Properties) - Exercise 19 (D)

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सेलिना Concise Mathematics [English] Class 6 ICSE
अध्याय 14 Fundamental Concepts (Including Angles and their Properties)
Exercise 19 (D) | Q 3.7
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