हिंदी

Distinguish Between the Given Pairs of Compounds Using the Test Given Within Brackets: Dilute Sulphuric Acid and Dilute Hydrochloric Acid (Using Barium Chloride Solution)

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प्रश्न

Distinguish between the given pairs of compounds using the test given within brackets:

Dilute sulphuric acid and dilute hydrochloric acid (using barium chloride solution)

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उत्तर

Sulphuric acid precipitates the insoluble sulphate of barium from the solution of barium chloride

BaCl2 + H2SO4 → BaSO4 + 2HCl

Dilute HCl does not react with barium chloride solution, and thus, no precipitate is produced in the reaction.

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2013-2014 (March) Science Paper 2

संबंधित प्रश्न

Which property of sulphuric acid is shown by the reaction of the concentrated sulphuric acid with ethanol?


Name the products formed when hot and concentrated sulphuric acid reacts with Sugar.


Name the products formed when hot and concentrated sulphuric acid reacts with Carbon.


Name the Following:
The property used to prepare HCl and HNO3 from H2SO4.


What would you observe in the following case?
Concentrated sulphuric acid is added to equal volumes of cold water.


What would you observe in the following case?
Hot concentrated sulphuric acid is added to sodium chloride crystals.


Copy and complete the following table.
Column 3 has the names of gases to be prepared using the substance you enter in column 1, along with dilute or concentrated sulphuric acid, as indicated in column 2.

Column 1 Column 2 Column 3
Substance reacted with acid Dilute or concentrated sulphuric acid Gas
    Hydrogen
    Carbon dioxide
    Only chlorine

Write the equation for the laboratory preparation of :
(i) Sodium sulphate using dilute sulphuric acid.
(ii) Lead sulphate using dilute sulphuric acid.


  1. Name the catalyst which helps in the conversion of sulphur dioxide to sulphur trioxide in step C.
  2. In the contact process for the manufacture of sulphuric acid, sulphur trioxide is not converted to sulphuric acid by reacting it with water. Instead a two-step procedure is used. Write the equations for the two steps involved in D.
  3. What type of substance will liberate sulphur dioxide from sodium sulphite in step E?
  4. Write the equation for the reaction by which sulphur dioxide is converted to sodium sulphite in step F.

Write balanced chemical equation to show :
The dehydrating property of conc. sulphuric acid


Identify the gas evolved and give the chemical test in the following case:

Dilute hydrochloric acid reacts with iron (II) sulphide.


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