Question

Discuss the method of fixing byes in knock-out tournament.

Answer 1

Steps to fix byes:

1. Find the next higher number in power of 2 from the total number of teams.
2. Number of byes = Next higher power of 2 − Total number of teams.
3. Divide teams equally into upper half and lower half. For odd teams, upper half = \[\frac{n+1}{2}\] and lower half = \[\frac{n-1}{2}\].
4. Divide byes: if byes are even, equal in both halves; if odd, upper half = \[\frac{nb-1}{2}\] and lower half = \[\frac{nb+1}{2}\].
5. Place byes as: 1st bye at bottom of lower half, 2nd at top of upper half, 3rd at top of lower half, 4th at bottom of upper half, and continue the same pattern.