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प्रश्न
Discuss the formation of N2 molecule using MO Theory.
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उत्तर
Molecular orbital diagram of nitrogen molecule (N2)
Electronic configuration of N atom 1s2 2s2 2p3
Electronic configuration of N2 molecule:
σ1s2, σ1s*2, σ2s2, σ2s*2, π2py2, π2pz2 σ2px2
Bond order = `("N"_"b" - "N"_"a")/2`
`= (10 - 4)/2` = 3
Molecule has no unpaired electrons hence it is diamagnetic.
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संबंधित प्रश्न
Draw an orbital diagram of Hydrogen fluoride molecule
Assertion: Oxygen molecule is paramagnetic.
Reason: It has two unpaired electron in its bonding molecular orbital.
Which of the following statements is INCORRECT?
Which one of the following sets CORRECTLY represents the increase in the paramagnetic property of the ions?
According to molecular orbital theory, antibonding molecular orbitals of O2 contain ____________.
According to molecular orbital theory, which of the following will NOT be viable?
Which element among the following does NOT form diatomic molecules?
Bonding in which of the following diatomic molecule(s) become(s) stronger, on the basis of MO Theory, by removal of an electron?
(A) NO
(B) N2
(C) O2
(D) C2
(E) B2
Choose the most appropriate answer from the options given below:
Which element among the following does not form diatomic molecules?
According to MO theory which of the following lists ranks the nitrogen species in terms of increasing bond order?
