Question

Differentiate the following w.r.t.x. :

y = x³ log x

Answer 1

Let y = x³ log x

∴ `("d"y)/("d"x) = "d"/("d"x) [x^3 log x]`

= `x^3 "d"/("d"x) (logx) + (logx) "d"/("d"x) (x^3)`

= `x^3 (1/x) + (log x)(3x^2)`

= x² + 3x² log x

= x² (1 + 3 log x)