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Differentiate the following function w.r.t.x. : (2ex-1)(2ex+1)

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प्रश्न

Differentiate the following function w.r.t.x. : `((2"e"^x - 1))/((2"e"^x + 1))`

योग
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उत्तर

Let y =`(2"e"^x - 1)/(2"e"^x + 1)`

Differentiating w.r.t. x, we get

`dy/dx=d/dx((2"e"^x - 1)/(2"e"^x + 1))`

= `((2"e"^x + 1)d/dx(2"e"^x - 1) - (2"e"^x - 1)d/dx(2"e"^x + 1))/((2"e"^x + 1)^2)`

= `((2"e"^x + 1)(2"e"^x - 0) - (2"e"^x - 1)(2"e"^x))/((2"e"^x + 1)^2)`

= `((2"e" + 1)(2"e"^x) - (2"e"^x - 1)(2"e"^x))/((2"e"^x - 1))`

= `(2"e"^x(2"e"^x + 1 - 2"e"^x + 1))/((2"e"^x + 1)^2)`

= `(2"e"^x(2))/((2"e"^x + 1)^2`

=  `(4"e"^x)/(2"e"^x + 1)^2`

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Rules of Differentiation (Without Proof)
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 9: Differentiation - Exercise 9.2 [पृष्ठ १२२]

APPEARS IN

बालभारती Mathematics and Statistics (Commerce) Part 1 [English] Standard 11 Maharashtra State Board
अध्याय 9 Differentiation
Exercise 9.2 | Q I. (7) | पृष्ठ १२२

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