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प्रश्न
Differentiate tan2 x ?
योग
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उत्तर
Let y = \[tan^2 x\]
\[\text{ Differentiating with respect to x we get }, \]
\[\frac{d y}{d x} = 2 \tan x\frac{d}{dx}\left( \tan x \right) .......\left[ \text{ using chain rule } \right]\]
\[ = 2 \tan x \times \sec^2 x \]
\[So, \frac{d}{dx}\left( \tan^2 x \right) = 2 \tan x \sec^2 x\]
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