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Differentiate Sin − 1 ( 1 − X 2 1 + X 2 ) + Sec − 1 ( 1 + X 2 1 − X 2 ) , X ∈ R ? - Mathematics

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प्रश्न

Differentiate \[\sin^{- 1} \left( \frac{1 - x^2}{1 + x^2} \right) + \sec^{- 1} \left( \frac{1 + x^2}{1 - x^2} \right), x \in R\] ?

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उत्तर

\[\text{ Let, y} = \sin^{- 1} \left( \frac{1 - x^2}{1 + x^2} \right) + se c^{- 1} \left( \frac{1 + x^2}{1 - x^2} \right)\]

\[ \Rightarrow y = \sin^{- 1} \left( \frac{1 - x^2}{1 + x^2} \right) + \cos^{- 1} \left( \frac{1 - x^2}{1 + x^2} \right) \left[ Since, se c^{- 1} x = \cos^{- 1} \left( \frac{1}{x} \right) \right]\]

\[ \Rightarrow y = \frac{\pi}{2} \left[ \text{ Since }, \sin^{- 1} x + \cos^{- 1} x = \frac{\pi}{2} \right]\]

Differentiate it with respect to x,

\[\therefore \frac{d y}{d x} = 0\] 

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अध्याय 11: Differentiation - Exercise 11.03 [पृष्ठ ६३]

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आरडी शर्मा Mathematics [English] Class 12
अध्याय 11 Differentiation
Exercise 11.03 | Q 24 | पृष्ठ ६३

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