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Differentiate Sin − 1 ( 1 √ 1 + X 2 ) ?

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प्रश्न

Differentiate \[\sin^{- 1} \left( \frac{1}{\sqrt{1 + x^2}} \right)\] ?

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उत्तर

\[\text{ Let, y } = \sin^{- 1} \left( \frac{1}{\sqrt{1 + x^2}} \right)\]

\[\text{ put x } = cot \theta\]

\[ \therefore y = \sin^{- 1} \left( \frac{1}{\sqrt{1 + co t^2 \theta}} \right)\]

\[ \Rightarrow y = \sin^{- 1} \left( \frac{1}{\sqrt{\cos e c^2 \theta}} \right)\]

\[ \Rightarrow y = \sin^{- 1} \left( \sin\theta \right) \]

\[ \Rightarrow y = \theta\]

\[ \Rightarrow y = co t^{- 1} x .............\left[ \text{since, }cot\theta = x \right]\]

Differentiate it with respect to x,

\[\frac{d y}{d x} = - \frac{1}{\left( 1 + x^2 \right)}\]

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 10: Differentiation - Exercise 11.03 [पृष्ठ ६३]

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आर.डी. शर्मा Mathematics Volume 1 and 2 [English] Class 12
अध्याय 10 Differentiation
Exercise 11.03 | Q 22 | पृष्ठ ६३
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