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Differentiate (Log Sin X)2 ? - Mathematics

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प्रश्न

Differentiate (log sin x)?

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उत्तर

\[\text{Let } y = \left( \log \sin x \right)^2 \]

\[\text{ Differentiate with respect to x we get }, \]

\[\frac{d y}{d x} = \frac{d}{dx} \left( \log \sin x \right)^2 \]

\[ = 2\left( \log \sin x \right)\frac{d}{dx}\left( \log \sin x \right)\]

\[ = 2\left( \log \sin x \right) \times \frac{1}{\sin x}\frac{d}{dx}\left( \sin x \right)\]

\[ = 2\left( \log \sin x \right) \times \frac{1}{\sin x} \times \cos x \]

\[ = 2\left( \log \sin x \right)\cot x\]

\[So, \frac{d}{dx} \left( \log \sin x \right)^2 = 2\left( \log \sin x \right)\cot x\]

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अध्याय 11: Differentiation - Exercise 11.02 [पृष्ठ ३७]

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आरडी शर्मा Mathematics [English] Class 12
अध्याय 11 Differentiation
Exercise 11.02 | Q 18 | पृष्ठ ३७

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