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Differentiate E Sin √ X ?

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प्रश्न

Differentiate \[e^{\sin} \sqrt{x}\] ?

योग
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उत्तर

\[Let y = e^{\sin}\sqrt{x} \]

\[\text{Differentiate it with respect to x we get}, \]

\[\frac{d y}{d x} = \frac{d}{dx}\left( e^{\sin}\sqrt{x} \right)\]

\[ = e^{\sin}\sqrt{x} \frac{d}{dx}\left( \sin\sqrt{x} \right) \left[ \text{using chain rule} \right]\]

\[ = e^{\sin}\sqrt{x} \times \cos\sqrt{x}\frac{d}{dx}\sqrt{x} \left[ \text{using chain rule } \right]\]

\[ = e^{\sin }\sqrt{x} \times \cos\sqrt{x} \times \frac{1}{2\sqrt{x}}\]

\[ = \frac{\cos\sqrt{x} e^{\sin}\sqrt{x}}{2\sqrt{x}}\]

\[So, \frac{d}{dx}\left( e^{\sin}\sqrt{x} \right) = \frac{\cos\sqrt{x} e^{ \sin }\sqrt{ x}}{2\sqrt{x}}\]

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 10: Differentiation - Exercise 11.02 [पृष्ठ ३७]

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आर.डी. शर्मा Mathematics Volume 1 and 2 [English] Class 12
अध्याय 10 Differentiation
Exercise 11.02 | Q 5 | पृष्ठ ३७
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