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Diagonals of a trapezium PQRS intersect each other at the point O. If PQ || RS and PQ = 3RS, then `(ar(ΔPOQ))/(ar(ΔROS))` = ______.
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Diagonals of a trapezium PQRS intersect each other at the point O. If PQ || RS and PQ = 3RS, then `(ar(ΔPOQ))/(ar(ΔROS))` = 9.
Explanation:
In triangles POQ and ROS, ∠QOP = ∠SOR (vertically opposite) and corresponding angles formed by PQ || RS are equal, so the triangles are similar (AA).
Hence the ratio of their areas equals the square of the ratio of corresponding sides: `(PQ)/(RS^2) = 3^2 = 9`.
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