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प्रश्न
Determine whether the following function is odd or even?
f(x) = `log (x^2 + sqrt(x^2 + 1))`
योग
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उत्तर
f(-x) = log((-x)2 + `sqrt((- x)^2 + 1)`
= log `(x^2 + sqrt(x^2 + 1))`
Thus f(-x) = f(x)
∴ f(x) is an even function.
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Functions and Their Graphs
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 5: Differential Calculus - Exercise 5.1 [पृष्ठ १०५]
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