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Determine Two Consecutive Multiples of 3, Whose Product is 270.

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Determine two consecutive multiples of 3, whose product is 270.

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Let the two consecutive multiples of 3 are 3x and 3x + 3

Given that their product is 270

⇒ (3x) (3x + 3) = 270

⇒ x(3x + 3) = 90

⇒ ЁЭСе2 + ЁЭСе - 30 = 0

⇒ ЁЭСе2 + 6ЁЭСе - 5ЁЭСе - 30 = 0

⇒ x(x + 6) - 5(x + 6) = 0

⇒ (x + 6) (x - 5) = 0

⇒ x = 5 or x = -6

Considering the positive value of x.

⇒ x = 5, 3x = 15 and 3x + 3 = 18

∴ The two consecutive multiples of 3 are 15 and 18.

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рдЕрдзреНрдпрд╛рдп 4: Quadratic Equations - Exercise 4.7 [рдкреГрд╖реНрда релреи]

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рдЖрд░.рдбреА. рд╢рд░реНрдорд╛ Mathematics [English] Class 10
рдЕрдзреНрдпрд╛рдп 4 Quadratic Equations
Exercise 4.7 | Q 20 | рдкреГрд╖реНрда релреи

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