Advertisements
Advertisements
प्रश्न
Determine the shortest wavelengths of Balmer and Pasch en series. Given the limit for the Lyman series is 912 Å.
Advertisements
उत्तर
The wavelength of lines are given by,
`1/lambda = "R"_"H" (1/"n"^2 - 1/"m"^2)`
For lyman series limit. n = 1. m = ∞
`therefore 1/lambda_"L" = "R"_"H" (1/1^2 - 1/oo) = "R"_"H"`
`therefore lambda_"L" = 1/"R"_"H" = 912`Å
For Balmer series limit, n = 2, m = ∞
`therefore 1/lambda_"B" = "R"_"H" (1/2^2 - 1/oo) = "R"_"H"/4`
`therefore lambda_"B" = 4/"R"_"H"`
= 4 × 912
= 3648 Å
For Paschen series limit. n = 3, m = ∞
`1/lambda_"P" = "R"_"H" (1/3^2 - 1/oo) = "R"_"H"/9`
`therefore lambda_"P" = 9/"R"_"H" = 9 xx 912`
= 8208 Å
APPEARS IN
संबंधित प्रश्न
In both β− and β+ decay processes, the mass number of a nucleus remains the same, whereas the atomic number Z increases by one in β− decay and decreases by one in β+ decay. Explain giving reason.
In the figure below, D and E respectively represent
If wavelength for a wave is `lambda = 6000 Å,` then wave number will be ____________.
Which of the following transition will have highest emission frequency?
In hydrogen atom, the product of the angular momentum and the linear momentum of the electron is proportional to (n = principal quantum number) ____________.
In hydrogen spectrum, which of the following spectral series lies in ultraviolet region?
In hydrogen spectrum, the series of lines obtained in the ultraviolet region of the spectrum is ____________.
Each element is associated with a ______.
An electron makes a transition from orbit n = 4 to the orbit n = 2 of a hydrogen atom. What is the wave number of the emitted radiations? (R = Rydberg's constant)
Absorption line spectrum is obtained ______.
To produce an emission spectrum of hydrogen it needs to be ______.
What is the minimum energy that must be given to a H atom in ground state so that it can emit an Hγ line in Balmer series. If the angular momentum of the system is conserved, what would be the angular momentum of such Hγ photon?
Deutrium was discovered in 1932 by Harold Urey by measuring the small change in wavelength for a particular transition in 1H and 2H. This is because, the wavelength of transition depend to a certain extent on the nuclear mass. If nuclear motion is taken into account then the electrons and nucleus revolve around their common centre of mass. Such a system is equivalent to a single particle with a reduced mass µ, revolving around the nucleus at a distance equal to the electron-nucleus separation. Here µ = meM/(me + M) where M is the nuclear mass and m e is the electronic mass. Estimate the percentage difference in wavelength for the 1st line of the Lyman series in 1H and 2H. (Mass of 1H nucleus is 1.6725 × 10–27 kg, Mass of 2H nucleus is 3.3374 × 10–27 kg, Mass of electron = 9.109 × 10–31 kg.)
Determine the series limit of Balmer, Paschen and Brackett series, given the limit for Lyman series is 911.6 Å.
Find the wavelength and wave number of the first member of the Balmer series in Hydrogen spectrum. (`R =1.097xx10^7m^(-1)`)
The de-Broglie wavelength of the electron in the hydrogen atom is proportional to ______.
What type of spectrum is obtained when an atomic gas or vapour at low pressure is excited and emits radiation of certain wavelengths?
What condition of an atomic gas or vapour produces an emission line spectrum?
Which radiation does an emission line spectrum contain?
The hydrogen spectrum is an example of which type of spectrum?
What is passed through an atomic gas or vapour to produce an absorption spectrum?
