Advertisements
Advertisements
प्रश्न
What is the minimum energy that must be given to a H atom in ground state so that it can emit an Hγ line in Balmer series. If the angular momentum of the system is conserved, what would be the angular momentum of such Hγ photon?
Advertisements
उत्तर
We know that Hγ spectral line in the Balmer series is formed when an electron falls from n = 5 to n = 1.
Here the electron is in the ground state ie., n = 1 and must be taken to n = 5 for Hγ line.
So the energy of H? = `E_5 - E_1 = (13.6/5^2) - (- 13.6)`
= – 0.54 + 13.6
= 13.06 eV
Since angular momentum, is conserved, so the angular momentum of Hγ = change in angular momentum of the electron
= L5 – L2 – 5h – 2h
= 3h = 3 × 6.63 × 10–34
= 19.89 × 10–34 kg m2/s
APPEARS IN
संबंधित प्रश्न
What is the shortest wavelength present in the Paschen series of spectral lines?
In both β− and β+ decay processes, the mass number of a nucleus remains the same, whereas the atomic number Z increases by one in β− decay and decreases by one in β+ decay. Explain giving reason.
Determine the series limit of Balmer, Paschen, and Pfund series, given the limit for Lyman series is 912 Å.
In the figure below, D and E respectively represent
Which of the following is TRUE?
Let the series limit for Balmer series be 'λ1' and the longest wavelength for Brackett series be 'λ2'. Then λ1 and λ2 are related as ______.
Let v1 and v3 be the frequency for series limit of Balmer and Paschen series respectively. If the frequency of first line of Balmer series is v2 then, relation between v1 and v2 and v3 is ____________.
In hydrogen atom, the product of the angular momentum and the linear momentum of the electron is proportional to (n = principal quantum number) ____________.
If the mass of the electron is reduced to half, the Rydberg constant ______.
Each element is associated with a ______.
Absorption line spectrum is obtained ______.
To produce an emission spectrum of hydrogen it needs to be ______.
Show that the first few frequencies of light that is emitted when electrons fall to the nth level from levels higher than n, are approximate harmonics (i.e. in the ratio 1 : 2 : 3...) when n >> 1.
Deutrium was discovered in 1932 by Harold Urey by measuring the small change in wavelength for a particular transition in 1H and 2H. This is because, the wavelength of transition depend to a certain extent on the nuclear mass. If nuclear motion is taken into account then the electrons and nucleus revolve around their common centre of mass. Such a system is equivalent to a single particle with a reduced mass µ, revolving around the nucleus at a distance equal to the electron-nucleus separation. Here µ = meM/(me + M) where M is the nuclear mass and m e is the electronic mass. Estimate the percentage difference in wavelength for the 1st line of the Lyman series in 1H and 2H. (Mass of 1H nucleus is 1.6725 × 10–27 kg, Mass of 2H nucleus is 3.3374 × 10–27 kg, Mass of electron = 9.109 × 10–31 kg.)
Determine the series limit of Balmer, Paschen and Brackett series, given the limit for Lyman series is 911.6 Å.
In the hydrogen atoms, the transition from the state n = 6 to n = 1 results in ultraviolet radiation. Infrared radiation will be obtained in the transition.
Calculate the wavelength of the first two lines in the Balmer series of hydrogen atoms.
