Question

Determine the nature of the roots for the following quadratic equation

9a²b²x² – 24abcdx + 16c²d² = 0, a ≠ 0, b ≠ 0

Answer 1

Here a = 9a²b²; b = – 24 abed, c = 16c²d²

∆ = b² – 4ac

= (– 24abcd)² – 4(9a²b²) (16c²d²)

= 576a²b²c²d² – 576a²b²c²d²

∆ = 0

So the equation will have real and equal roots.