Question

Determine the nature of roots of the following quadratic equation.

 2y² – 7y + 2 = 0

Answer 1

2y² – 7y + 2 = 0

Comparing 2y² − 7y + 2 = 0 with the standard form ay² + by + c = 0.

a = 2, b = – 7, c = 2

Δ = b² − 4ac

Δ = (– 7)² − 4(2)(2)

Δ = 49 − 16

Δ = 33
Since the discriminant > 0 so, the roots of the given quadratic equation are real and unequal.