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प्रश्न
Determine the nature of root of the following:
`x^2 + 2sqrt(3x) - 1 = 0`
योग
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उत्तर
Given:
From the equation:
a = 1
b = `2sqrt3`
c = −1
Substitute the values:
D = b2 − 4ac
`D = (2sqrt3)^2 - 4(1)(-1)`
= 4 ⋅ 3 + 4
= 12 + 4
= 16
Discriminant D = 16 > 0
And D is a perfect square
The roots are real, distinct, and rational.
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