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प्रश्न
Determine the empirical formula of an oxide of iron, which has 69.9% iron and 30.1% dioxygen by mass.
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उत्तर
% of iron by mass = 69.9 % [Given]
% of oxygen by mass = 30.1 % [Given]
Relative moles of iron in iron oxide:
`= (% "of iron by mass")/("Atomic mass of iron")`
`= 69.9/55.85`
= 1.25
Relative moles of oxygen in iron oxide:
`= (% "of oxygen by mass")/("Atomic mass of oxygen")`
`= 30.1/16.00`
= 1.88
Simplest molar ratio of iron to oxygen:
= 1.25 : 1.88
= 1 : 1.5
= 2 : 3
∴ The empirical formula of the iron oxide is Fe2O3.
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