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प्रश्न
Derive the relation pH + pOH = 14.
Derive the relationship between pH and pOH.
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उत्तर
Relationship between pH and pOH:
The ionic product of water is given as:
Kw = [H3O+][OH–]
Now, Kw = 1 × 10−14 at 298 K
Thus, [H3O+][OH-] = 1 × 10−14
Taking the logarithm of both the sides, we write
log10[H3O+] + log10[OH-] = -14
-log10[H3O+] + {-log10[OH-]} = 14
Now, pH = -log10[H3O+] and pOH = -log10[OH-]
∴ pH + pOH = 14
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