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प्रश्न
Define a class to accept a string and convert the same to uppercase, create and display the new string by replacing each vowel by immediate next character and every consonant by the previous character. The other characters remain the same.
Example: Input: #IMAGINATION@2024
Output: #JLBFJMBSJPM@2024
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उत्तर
class convert
{
String s;
convert(String z)
{
s=z
}
void convert()
{
int i, l=s.length();char ch;String ns="";
for(i=0;i<l;i++)
{
ch=s.charAt(i);
if(Character.isLetter(ch))
{
if("AEIOUaeiou".indexOf(ch)>=0)
ns=ns+(char)(ch+1);
else
ns=ns+(char)(ch-1);
}
else
ns=ns+ch;
}
System.out.print(ns);
}
}APPEARS IN
संबंधित प्रश्न
Give the output of the following code:
String P = “20”, Q = “19”,
int a = Integer .parselnt(P);
int b = Integer. valueOf(Q);
System.out.println(a+””+b);
State the data type and value of res after the following is executed:
char ch = ‘t’;
res=Character. toUpperCase(ch);
Write a difference between the functions isUpperCase() and toUpperCase().
int res = ‘A’;
What is the value of res?
Write a program to accept a number and check and display whether it is a Niven number or not.
(Niven number is that number which is divisible by its sum of digits).
Example:
Consider the number 126.
The Sum of its digits is 1+2+6 = 9 and 126 is divisible by 9.
What is the data type returned by the library function?
compareTo()
What will be the output when the following code segment is executed?
String s = “1001”;
int x = Integer. valueOf(s);
double y = Double.valueOf(s);
System.out.println(“x=”+x);
System.out.println(“y=”+y);
What is the method to check whether a character is a letter or digit?
Predict the output of the following code snippet:
char ch='B';
char chr=Character.toLowerCase(ch);
int n=(int)chr-10;
System.out.println((char)n+"\t"+chr);
A student is trying to convert the string present in x to a numerical value, so that he can find the square root of the converted value, However the code has an error. Name the error (syntax/logical/runtime). Correct the code so that it compiles and runs correctly.
String x="25";
int y=Double.parseDouble(x);
double r=Math.sqrt(y);
System.out.println(r);