Advertisements
Advertisements
प्रश्न
D, E, F are the mid-point of the sides BC, CA and AB respectively of ΔABC. Then ΔDEF is congruent to triangle
विकल्प
ABC
AEF
BFD, CDE
AFE, BFD, CDE
Advertisements
उत्तर
It is given that D, E and Fare the mid points of the sides BC , CA and AB respectively of ΔABC
FE =BD (By mid point theorem)
BD = DC (As it is mid point)
Now in ΔAFE and ΔDFE
FE(Common)
DF = AE (Mid point)
AF = DE (Mid point)
⇒ ΔFED ≅ ΔBFD
⇒ ΔDFE ≅ ΔDCE
Hence (d)
ΔDFE ≅ AFE
≅ BFD
≅ CDE
APPEARS IN
संबंधित प्रश्न
You want to show that ΔART ≅ ΔPEN,
If it is given that ∠T = ∠N and you are to use SAS criterion, you need to have
1) RT = and
2) PN =
In a triangle ABC, D is mid-point of BC; AD is produced up to E so that DE = AD. Prove that:
AB = CE.
A triangle ABC has ∠B = ∠C.
Prove that: The perpendiculars from B and C to the opposite sides are equal.
From the given diagram, in which ABCD is a parallelogram, ABL is a line segment and E is mid-point of BC.
Prove that: AB = BL.
In the given figure, AB = DB and Ac = DC.
If ∠ ABD = 58o,
∠ DBC = (2x - 4)o,
∠ ACB = y + 15o and
∠ DCB = 63o ; find the values of x and y.
In the following figure, AB = AC and AD is perpendicular to BC. BE bisects angle B and EF is perpendicular to AB.
Prove that : ED = EF
In the figure, given below, triangle ABC is right-angled at B. ABPQ and ACRS are squares. 
Prove that:
(i) ΔACQ and ΔASB are congruent.
(ii) CQ = BS.
In the following figure, OA = OC and AB = BC.
Prove that: ΔAOD≅ ΔCOD
AD and BC are equal perpendiculars to a line segment AB. If AD and BC are on different sides of AB prove that CD bisects AB.
In a triangle, ABC, AB = BC, AD is perpendicular to side BC and CE is perpendicular to side AB.
Prove that: AD = CE.
