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प्रश्न
Construct a quadrilateral ABCD, where AB = 5.5 cm, BC = 3.7 cm, ∠A = 60°, ∠B = 105° and ∠D = 90°.
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उत्तर
We know that the sum of all the angles in a quadrilateral is 360 .
i . e . , ∠A + ∠B + ∠C + ∠D = 360°
⇒ ∠C = 105°
Steps of construction:
Step I: Draw AB = 5 . 5 cm .
Step II: Construct ∠XAB = 60° at A and ∠ABY = 105° .
Step III: With B as the centre and radius 3 . 7 cm, cut off BC = 3 . 7 cm .
Step IV: At C, draw ∠BCZ = 105° such that it meets AX at D .
The quadrilateral so obtained is the required quadrilateral .

संबंधित प्रश्न
Construct, if possible, a quadrilateral ABCD in which AB = 6 cm, BC = 7 cm, CD = 3 cm, AD = 5.5 cm and AC = 11 cm. Give reasons for not being able to construct, if you cannot. (Not possible, because in triangle ACD, AD + CD < AC).
Construct a quadrilateral ABCD in which AB = 3.8 cm, BC = 3.0 cm, AD = 2.3 cm, AC = 4.5 cm and BD = 3.8 cm.
Construct a quadrilateral ABCD in which AB = BC = 3 cm, AD = CD = 5 cm, and ∠B = 120°.
Construct a quadrilateral ABCD in which AB = 2.8 cm, BC = 3.1 cm, CD = 2.6 cm, and DA = 3.3 cm and ∠A = 60°.
Construct a quadrilateral ABCD, where AB = 4.2 cm, BC = 3.6 cm, CD = 4.8 cm, ∠B = 30° and ∠C = 150°.
Construct a quadrilateral PQRS, in which PQ = 3.5 cm, QR = 2.5 cm, RS = 4.1 cm, ∠Q = 75° and ∠R = 120°.
Construct a quadrilateral PQRS, in which ∠Q = 45°, ∠R = 90°, QR = 5 cm, PQ = 9 cm and Rs = 7 cm.
Construct a quadrilateral BDEF, where DE = 4.5 cm, EF = 3.5 cm, FB = 6.5 cm, ∠F = 50° and ∠E = 100°.
Construct a quadrilateral ABCD, where ∠A = 65°, ∠B = 105°, ∠C = 75° BC = 5.7 cm and CD = 6.8 cm.
A quadrilateral can be constructed uniquely if three angles and any two sides are given.
