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प्रश्न
Construct an isosceles triangle in which: PQ = QR, PR = 4.5 cm and ∠R = 60°
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उत्तर
In ΔPQR,
PQ = QR ....(given)
⇒ ∠PRQ = ∠RPQ = 60°
Steps:
1. Draw PR = 4.5cm.
2. Construct ∠PRU = 60° and ∠RPV = 60
3. Ray RU and PV meet at Q.
Thus, PQR is the required triangle.
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संबंधित प्रश्न
In ∆ PQR, l(PQ) = 6 cm, l(QR) = 3.8 cm, l(PR) = 4.5 cm
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