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प्रश्न
Construct an angle PQR = 45°. Mark a point S on QR such that QS = 4.5 cm. Construct a circle to touch PQ at Q and also to pass through S.
योग
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उत्तर
Steps of constructions:
(i) Draw ∠ PQX = 90°
(ii) Bisects ∠ PQX and draw ∠ PQR = 45°
(iii) Cut off QS = 4.5 cm from QR.
(iv) r bisector of QS and it intersects of QX at O.
(v) With O as centre and radius = OQ ( or OS draw the required circle).
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