Question

Construct a triangle ABC, having given AB = 4.8 cm, AC = 4 cm, and ∠A = 75°. Find a point P.

1. inside the triangle ABC.
2. outside the triangle ABC

Equidistant from B and C; and at a distance of 1.2 cm from BC.

Answer 1

  

Steps of construction:

1. Draw a line segment AB = 4.8 cm
2. At A, draw a ray AX making an angle of 75°
3. Cut off AC = 4 cm from AX
4. Join BC.
   ABC is the required triangle.
5. Draw two lines l and m parallel to BC at a distance of 1.2 cm
6. Draw the perpendicular bisector of BC which intersects l and m at P and P’
   P and P’ are the required points which are inside and outside the given triangle ABC.