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Construct a quadratic equation with roots 7 and −3

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प्रश्न

Construct a quadratic equation with roots 7 and −3

योग
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उत्तर

The given roots are 7 and – 3

Let α = 7 and β = – 3

α + β = 7 – 3 = 4

αβ = (7)(– 3) = – 21

The quadratic equation with roots α and β is x2 – (α + β) x + αβ = 0

So the required quadratic equation is

x2 – (4) x + (– 21) = 0

(i.e.,) x2 – 4x – 21 = 0

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Quadratic Functions
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अध्याय 2: Basic Algebra - Exercise 2.4 [पृष्ठ ६२]

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सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
अध्याय 2 Basic Algebra
Exercise 2.4 | Q 1 | पृष्ठ ६२
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