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Construct a parallelogram PQRS, PQ = 4 cm, PR = 6 cm and QS = 8 cm. - Mathematics

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प्रश्न

Construct a parallelogram PQRS, PQ = 4 cm, PR = 6 cm and QS = 8 cm.

ज्यामितीय चित्र
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उत्तर

Given:

  • Parallelogram PQRS
  • Side PQ = 4 cm
  • Diagonal PR = 6 cm
  • Diagonal QS = 8 cm


Steps of construction:

  1. Draw a line segment PQ = 4 cm.
  2. Since PR and QS are diagonals of the parallelogram and they bisect each other, let O be the intersection point of the diagonals.
  3. Since PR = 6 cm, PO = OR = 3 cm (half of PR).
  4. Since QS = 8 cm, QO = OS = 4 cm (half of QS).
  5. At point P, draw an arc of radius 3 cm (for PO).
  6. At point Q, draw an arc of radius 4 cm (for QO).
  7. Let these arcs intersect at point O, the midpoint of both diagonals.
  8. Using the midpoint O, construct the parallelogram by drawing the remaining vertices R and S, ensuring the diagonals bisect each other.
  9. Join points PR and QS to complete parallelogram PQRS.

By drawing side PQ as 4 cm and locating point O by bisecting the diagonals PR = 6 cm and QS = 8 cm at half lengths, the parallelogram PQRS can be accurately constructed with its diagonals intersecting at O, maintaining the properties of a parallelogram.

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अध्याय 12: Rectilinear Figures (Theorems on Parallelograms and Construction of Polygons) - MISCELLANEOUS EXERCISE [पृष्ठ १५२]

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बी निर्मला शास्त्री Mathematics [English] Class 9 ICSE
अध्याय 12 Rectilinear Figures (Theorems on Parallelograms and Construction of Polygons)
MISCELLANEOUS EXERCISE | Q II. 1. | पृष्ठ १५२
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