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प्रश्न
Construct a parallelogram ABCD in which AB = 4.5cm, ∠A = 105° and the distance between AB and CD is 3.2cm.
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उत्तर
Steps of construction:
1) Draw line AB = 4.5cm.
2) At B, draw BX perpendicular to AB.
3) From BX, cut BR = 3.2cm = distance between AB and CD.
4) Through R, draw a line perpendicular to BX to get QR parallel to AB.
5) With A as centre, draw a ray AP making an angle of 105 with AB and meeting QR at D.
6) With B as centre, draw an arc with radius = AD on QR and mark it as C.
7) Join BC.
8) ABCD is the required parallelogram.
संबंधित प्रश्न
Construct a parallelogram ABCD, when:
AB = 4.4 cm, AD = 6.2 cm and AC = 4.8 cm.
Draw parallelogram ABCD with the following data:
AB = 6 cm, AD = 5 cm and ∠DAB = 45o.
Let AC and DB meet in O and let E be the mid-point of BC. Join OE.
Prove that:
(i) OE // AB
(ii) OE = `1/2` AB.
Construct a parallelogram ABCD, when:
AB = 6.0 cm, AD = 5.0 cm and ∠A = 45°.
Using ruler and compasses only, construct a parallelogram ABCD using the following data: AB = 6 cm, AD = 3 cm and ∠DAB = 45o. If the bisector of ∠DAB meets DC at P,
prove that ∠APB is a right angle.
Construct a parallelogram ABCD, if :
AD = 4 cm, DC = 5 cm and diagonal BD = 7 cm.
Construct a parallelogram ABCD, if :
AB = 5.8 cm, AD = 4.6 cm and diagonal AC = 7.5 cm.
Using ruler and compasses only, construct a parallelogram ABCD, in which : AB = 6 cm, AD = 3 cm and ∠DAB = 60°. In the same figure draw the bisector of angle DAB and let it meet DC at point P. Measure angle APB.
Construct a parallelogram ABCD. Given:
AB = 5.5cm, BC = 3.5cm, ∠B = 75°
Construct a parallelogram ABCD. Given:
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Construct a parallelogram PQRS in which PQ = 6.4cm, QR = 4cm and the distance between PQ and SR is 3cm.
